1) a^1/3 + b^1/3 + c^1/3 = 0, then relation between a,b,c is 2) (x^b/x^c)^(b+c-a) * (x^c/x^a)^(c+a-b) * (x^a/x^b)^(a+b-c) is equal to 3) 1/(sq.rt(2) + 1) + 1/(sq.rt(3) + sq.rt(2)) + 1/(sq.rt(4) + sq.rt(3)) 4) x = ( sq.rt(3) + 1 )/( sq.rt(3) - 1 ) and y = ( sq.rt(3) - 1 )/( sq.rt(3) + 1 ) . Find x^2 + y^2 Watch solution here :
Preparation for Competitive exams SSC RAILWAY