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Showing posts from May 21, 2019

๐‘ฅ=4๐‘Ž๐‘/(๐‘Ž+๐‘) , Find (๐‘ฅ+2๐‘Ž)/(๐‘ฅ −2๐‘Ž) + (๐‘ฅ+2๐‘)/(๐‘ฅ −2๐‘)

๐‘Ž^2 + ๐‘^2 + 2b + 4a + 5 = 0 , Find (๐‘Ž −๐‘)/(๐‘Ž+๐‘)

๐‘Ž/(1−๐‘Ž) + ๐‘/(1−๐‘) + ๐‘/(1−๐‘) = -3 , Find 1/(1−๐‘Ž) + 1/(1−๐‘) + 1/(1−๐‘)

〖(๐‘Ž−3)〗^2 + 〖(๐‘−4)〗^2 + 〖(๐‘−9)〗^2 = 0 , Find √(๐‘Ž+๐‘+๐‘)

If 3x + 1/2๐‘ฅ = 5, Find the value of 8๐‘ฅ^3 + 1/(27๐‘ฅ^3 )

If ๐‘ฅ/(2๐‘ฅ^2+5๐‘ฅ+2) = 1/6 , Find the value of x + 1/๐‘ฅ

If xy(x+y) = 1 , Find value of 1/(๐‘ฅ^3 ๐‘ฆ^3 ) - ๐‘ฅ^3 - ๐‘ฆ^3